Vans, the leading skatewear brand, has joined forces with the MoMA (Museum of Modern Art) to create a unique collection that blends street style with contemporary art. The collaboration reflects the shared passion of both parties for individual forms of expression and showcases works by some of the world’s most renowned artists, including Salvador Dalí, Wassily Kandinsky, Claude Monet, Edvard Munch, Jackson Pollock, Ljubov Popova, and Faith Ringgold.
This exciting collaboration between Vans and MoMA presents a modern and gender-neutral skatewear collection that will appeal to both art lovers and streetwear enthusiasts. The first part of the collection, which will be released on September 30th, includes shoes, apparel, and accessories that were selected by Vans in collaboration with MoMA. This part of the collection is already available for purchase in the official Vans online shop, selected Vans stores, and the MoMA Design Store at store.moma.org.
The second part of the Vans and MoMA artist series will be released in November and will also feature works of art selected from the MoMA collection. The collection showcases the diversity of the MoMA collection and presents a unique blend of streetwear and contemporary art. The second part of the collection promises to be just as exciting as the first and will be available on Vans.de.
For those who are eager to learn more about this exciting collaboration, more information is available at vans.eu/moma. Keep an eye out for the second part of the Vans and MoMA artist series, as it is sure to be a hit among streetwear and art lovers alike.
Vans and MoMA have come together to create a unique collection that showcases the diversity of the MoMA collection and combines street style with contemporary art. The collection, which includes shoes, apparel, and accessories, is available for purchase in selected Vans stores, the MoMA Design Store, and the official Vans online shop. Stay tuned for the second part of the Vans and MoMA artist series, which promises to be just as exciting as the first.
